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View Full Version : The Official Bijou Riddle Thread!


Gaaraxxx
05-25-2008, 03:44 PM
Myself and friends always used to have fun on vent doing this, so I thought I'd throw it into thread form to spread the love.

Overview:
Want to prove you can think outside the box?
Show everyone your intellectual prowess now!
Simply answer the questions correctly and earn points based on the difficulty of the questions!

Rules and Regulations:

1. The points will be awarded to the first person with the correct answer, therefore: NO EDITING POSTS :D! You will not be credited if you do this ;).
2. Try to keep flaming, cursing, all that stuff to a minimum.
3. Have fun!


Keep in mind that I won't be around to cover this thread 24/7, so if anyone feels the need to keep it going, and keep it bumped, please feel free to do so!

Gaaraxxx
05-25-2008, 03:44 PM
Current Riddle:

How would you divide up 1000$ in to ten piles such that no matter what amount you were asked for, you could choose any combination of the piles to satisfy.

Worth: 4

Gaaraxxx
05-25-2008, 03:45 PM
High Score Table


Name: / Points:

Azn_InvaznXD: 12
shackelberry: 9
Cristo: 5
kitteh: 4

CristoPT
05-25-2008, 04:19 PM
Current Riddle:
Determine the next line that follows the pattern.
Worth: 5

1
1 1
2 1
1 2 1 1
1 1 1 2 2 1
3 1 2 2 1 1
1 3 1 1 2 2 2 1
1 1 1 3 2 1 3 2 1 1

Answer?

Previous Riddle:

Previous Winner:

3 1 1 3 1 2 1 1 1 3 1 2 2 1

Gaaraxxx
05-25-2008, 04:36 PM
Very impressive Cris :D!
Next one comin up XD

Strang3r
05-25-2008, 04:56 PM
DO we get any prize for the most points? :P

Gaaraxxx
05-25-2008, 04:57 PM
Chances are I'm going to leave this thread running as long as possible, see how much attention it gets :P.
So no guaranteed end time to begin with :D.
Besides that, your reward could be the feeling of satisfaction you'll have by outwitting the rest of the server.

Azn_InvaznXD
05-25-2008, 05:06 PM
[QUOTE=Gaaraxxx;717872]Current Riddle:

Three friends each pay 10$ for a hotel room.
The clerk admits to have made a mistake on the charges, and returns to them 3$.
The clerk uses this opportunity to pocket 2$ herself.
So the three friends have each payed 9$ for their respective rooms, the clerk has taken two dollars.
Where is the last dollar?
Explain.



There is no extra dollar; the clerk gets 30 dollars, notices 5 dollars extra, takes 2 dollars, and gives 3 back to each friend. so the total amount for the hotel would have been 25 dollars, clerk takes 2 for himself, 25+2=27, and gives 1 dollar back to each person, 25+2+3 = 30

phanthunderrage
05-25-2008, 05:08 PM
Current Riddle:

Three friends each pay 10$ for a hotel room.
The clerk admits to have made a mistake on the charges, and returns to them 3$.
The clerk uses this opportunity to pocket 2$ herself.
So the three friends have each payed 9$ for their respective rooms, the clerk has taken two dollars.
Where is the last dollar?
Explain.

Worth: 4



It still there on the desk

30 - 3 - 2 = 25 dollars remain on the desk
also mean : (9x3 - 2)

Actually, the question is wrong, there is no "last dollar"

phanthunderrage
05-25-2008, 05:11 PM
Ouch, i was late for 2min. Damn 1hand typing.

Cherushi
05-25-2008, 05:17 PM
Hoooray for intelligent people in Bijou!!! *lazy to solve the current riddles* =D


next one pl0x.... lol :P

Ouch, i was late. for 2min. Damn 1hand typing.

...LOL!

Azn_InvaznXD
05-25-2008, 05:19 PM
lol this one is old it was a warm up for math in like 7th grade XD

Gaaraxxx
05-25-2008, 05:45 PM
Okey riddle on its way then!
Maybe I come up with a better math-y one :)

shackelberry
05-25-2008, 05:55 PM
[QUOTE=Gaaraxxx;717872]Current Riddle:

Mark, while riding to work, gets stuck in traffic and averages 30mph on the way.
How fast must he travel in order to average 60mph on the round trip?

Worth: 4

[QUOTE]

whats the round trip?

Gaaraxxx
05-25-2008, 05:56 PM
The round trip would be the amount he travels to and from work.
I.E twice the distance he covered going 30mph.

shackelberry
05-25-2008, 05:58 PM
you dont mention when he get stuck on the road

Gaaraxxx
05-25-2008, 06:00 PM
Doesn't matter, I'm talking average speed :)

Edit: Oh, i see what you mean.
He makes it too work, but at a slower average speed. He doesn't actually give up or stop anywhere.

Azn_InvaznXD
05-25-2008, 06:01 PM
90 mph? explain it better lol x.x does he get stuck as soon as he gets in the car?

Gaaraxxx
05-25-2008, 06:02 PM
In general, he travels slower to work, than from work.
I want to know how fast he need travel in order to average 60 on his trip to and from.

shackelberry
05-25-2008, 06:04 PM
okay i get it now....

answear is he will go 90 mph per hour to get an average of 60 mph per hour..

30 + 90 = 120... 120 / 2 = 60

Gaaraxxx
05-25-2008, 06:05 PM
okay i get it now....

answear is he will go 90 mph per hour to get an average of 60 mph per hour..

30 + 90 = 120... 120 / 2 = 60

That is incorrect, but you understand what I mean by average, which is good.
The riddle itself is harder than that ;).

KanesAssassin
05-25-2008, 06:06 PM
For some reason I can only come up with 90mph on the last leg of the trip. Assuming hes gone an average of 30mph on the way to the workplace, he has another trip back to average it out to 60. Going 60mph the way back won't work because 30+60=90 then divided by the two legs of the trip is an average of 45. So I can only come up with the assumption that Mark has to go 90mph on the way, for 90+30=120 divided by 2 which is 60mph.

Of course, I have a nagging feeling I didn't read something right or something else and I now look really stupid lol.
Edit: already said thats wrong, which sucks v.v

Azn_InvaznXD
05-25-2008, 06:06 PM
90 mph? assuming theres no traffic, but then he'd get arrested for speeding! or maybe just a ticket lol

Gaaraxxx
05-25-2008, 06:08 PM
90 would be the obvious answer to choose, but think of it this way:
MPH is a fraction, right?
In order average 60MPH, 90MPH wouldnt work, because he will no longer be traveling for one hour.
Assuming it takes him one hour to get to work, then his trip from work will no longer take one hour because he's going three times as fast. (Because the distance he's travelling is the same.)

Hope that helps a bit ;). It's harder than it sounds.

KanesAssassin
05-25-2008, 06:09 PM
In general, he travels slower to work, than from work.
I want to know how fast he need travel in order to average 60 on his trip to and from.

Does the part where he averages 30mph count as part of the question? That would be half the trip, but if thats just something in there to mess a person up, then you would go 60mph all the way around to get an average of 60mph.

Edit:just saw your above post, disregard.

Gaaraxxx
05-25-2008, 06:10 PM
Does the part where he averages 30mph count as part of the question? That would be half the trip, but if thats just something in there to mess a person up, then you would go 60mph all the way around to get an average of 60mph.

Edit:just saw your above post, disregard.

Yes, the original 30MPH is part of his trip.
We're considering both the speed it took him to get to work, and the speed returning from.

KanesAssassin
05-25-2008, 06:15 PM
Yes, the original 30MPH is part of his trip.
We're considering both the speed it took him to get to work, and the speed returning from.

I'm a bit confused, it feels like you'd need to know how long it took him to get to work, and then to get back. If he took an hour with traffic to get there averaging 30mph, then on the way back goes 45mph for half an hour, without traffic then wouldnt the 45 be multiplied by 2, making it 90? I'm most likely grasping at straws lol, something I shouldn't be doing while I'm tired I guess.

IcyPhoenix
05-25-2008, 06:17 PM
60MPH on the round trip.

Gaaraxxx
05-25-2008, 06:22 PM
I'm a bit confused, it feels like you'd need to know how long it took him to get to work, and then to get back. If he took an hour with traffic to get there averaging 30mph, then on the way back goes 45mph for half an hour, without traffic then wouldnt the 45 be multiplied by 2, making it 90? I'm most likely grasping at straws lol, something I shouldn't be doing while I'm tired I guess.

But if you're going 45 'miles per hour' for half an hour, you can't say you would have travelled 90 miles in one hour. It would still be 45MPH.
In the end it doesn't matter how far it is, or how long it takes, because you can guess a number, and from it derive how long it would have taken for the same portion of the trip.
(The distance to and from is the same, so it doesn't really matter.)

Its confusing I know :D.
Maybe I should up the points awarded for figuring it out ;)

Gaaraxxx
05-25-2008, 06:29 PM
60MPH on the round trip.

Thats what we're trying to figure out, HOW would you get 60MPH for the round trip?

Azn_InvaznXD
05-25-2008, 06:30 PM
random number guess time 270! O.o?

Gaaraxxx
05-25-2008, 06:37 PM
BZZZZT! Incorrect.
YAY for mach 1 station wagons.

KanesAssassin
05-25-2008, 06:40 PM
Gonna guess that the trip back has to be done at a speed of light. Because his distance to work is 30 miles, so total its 60 miles. so if he normally goes 60mph, it takes one hour total, but he only went 30 this time, so he already burnt the hour. Assuming that, the only way to average it to stay at 60, is to be able to get home instantaneously, meaning the speed of light.

Edit: if not true, before I leave, I will assume that assuming this isn't right, that the question is illogical, that there is a piece of information still needed.

FiveFingers
05-25-2008, 06:53 PM
hmmm

So uhm d is the distance to work, T will be the time it takes Mark to get there, t will be the time it takes to get back, and R is gonna be the speed in wich old Mark travels on the on the way back (im confused already D: ) So erm uhm:

d = 30T
T = d/30

d = Rt
t = d/R

SO thats T and t and uhm

2d = 60(T + t)
2d = 60(d/0 + d/R)
2d = 60d(1/30 + 1/R)
1 = 30(R/30R + 30/30R)
30R = 30(R+30)
R = R + 30
So regardless of what R is, it will always be 30 more D:!

Confused? I am... Let me explain o.0

Basically the solution is Ø aka No solution. You have to travel at infinite speed back to get average speed of 60 MPH. Cuz like the faster you go, the faster u reach home or MArk does I don't D: SO the more speed the longer he needs to travel for it to have a major effect on the average speed
Basically due to the fact thats its infite (i cant do the sign for infinity), you end up with an average speed of 60 MPH


Hope I explained it in a sort of human way o.0

KanesAssassin
05-25-2008, 06:56 PM
hmmm

So uhm d is the distance to work, T will be the time it takes Mark to get there, t will be the time it takes to get back, and R is gonna be the speed in wich old Mark travels on the on the way back (im confused already D: ) So erm uhm:

d = 30T
T = d/30

d = Rt
t = d/R

SO thats T and t and uhm

2d = 60(T + t)
2d = 60(d/0 + d/R)
2d = 60d(1/30 + 1/R)
1 = 30(R/30R + 30/30R)
30R = 30(R+30)
R = R + 30
So regardless of what R is, it will always be 30 more D:!

Confused? I am... Let me explain o.0

Basically the solution is Ø aka No solution. You have to travel at infinite speed back to get average speed of 60 MPH. Cuz like the faster you go, the faster u reach home or MArk does I don't D: SO the more speed the longer he needs to travel for it to have a major effect on the average speed
Basically due to the fact thats its infite (i cant do the sign for infinite), you end up with an average speed of 60 MPH


Hope I explained it in a sort of human way o.0

thank god, I'm not crazy, someone thought the same thing.

Orchids_Mantis
05-25-2008, 07:16 PM
If you are trying to AVERAGE 60 mph, then he needs to go 90 on the way back, as was previously stated...if you are trying to remake the infamous bridge question, then you phrased it wrong...it's half the speed for half the distance of the first leg, how fast does he need to go to make the same time for the first crossing?

Gaaraxxx
05-25-2008, 07:25 PM
Im going to give credit to kitteh on this one, for explaining it best.
And it's true, regardless of 'R' the results are the same! :D

Azn_InvaznXD
05-25-2008, 07:44 PM
Current Riddle:

I couldn't come up with a hard one, so an easy one instead!
A large truck approaches a bridge with a max capacity of 20,000lbs.
The truck itself happens to have an exact wait of 20,000lbs as it approaches one end of the bridge.
While crossing the bridge, a bird lands on the truck, yet the bridge does not collapse.
Why?

Worth: 3





the truck used enough fuel by the time the bird landed so it doesn't weigh 20,000 pounds! right?

Gaaraxxx
05-25-2008, 07:51 PM
Yes, Right :D!

Azn_InvaznXD
05-25-2008, 07:55 PM
woot i <3 logic lol

Azn_InvaznXD
05-25-2008, 08:04 PM
one of the convicts friend robs a bank and gets into jail with blueprints of the jail tatooed onto his body and after a few months of digging during their break / work time they get out

Gaaraxxx
05-25-2008, 08:06 PM
Wheres your logic now?
ROFL.

Azn_InvaznXD
05-25-2008, 08:07 PM
wheres my 3 points? =.= lolz mm they can dig a hole, and use it as a toilet and use the dirt they dug up and make a ramp escaping?

Gaaraxxx
05-25-2008, 08:08 PM
Yes, lol.
The dirt from the hole makes a pile for their exit XD.

yourmojo
05-25-2008, 08:18 PM
What belongs to you, but is used more by others?

copyrighted material?

Azn_InvaznXD
05-25-2008, 08:19 PM
Current Riddle:

What belongs to you, but is used more by others?

Worth: 2





hmmmmmm your unpassworded wireless internet connection? or maybe your name unless you talk in third person all the time

Gaaraxxx
05-25-2008, 08:25 PM
He knows too many riddles :3.
Yes, its your name.

Azn_InvaznXD
05-25-2008, 08:58 PM
imma riddle master XD lol

FiveFingers
05-25-2008, 09:34 PM
there u go azn that riddle is pure logic, knock urself out :D!

Sir_Pyrate
05-26-2008, 03:55 AM
I am the beginning of eternity
The end of time and space
The beginning of every end
And the end of every place

What am I?

horong
05-26-2008, 04:22 AM
The letter E

phanthunderrage
05-26-2008, 04:27 AM
[B]Current Riddle:

Two mathematicians, Albert and Isaac, chat. Isaac says he has three children who all have the same birthday (but who weren't necessarily born in the same year). Albert asks their ages. Isaac replies, "The product of the ages of my children is 72." Albert points out that this is not enough information to determine their ages. Isaac responds with another clue -- he tells Albert the sum of the ages of his children. But Albert again points out that there is not enough information. Finally Isaac says, "My youngest child is named Galileo." At last, Albert correctly determines the ages of Isaac's children. What are the ages?


Previous Riddle:

Answer : 2 4 9

Galileo's Paradox (http://en.wikipedia.org/wiki/Galileo%27s_paradox)

shackelberry
05-26-2008, 04:27 AM
the answear to current riddle is: the youngest of his sons is 2 and the other are twins and both 6

Edit: phan there supposed be twins and yonger brother since issac only say is yongest son is named galilea

phanthunderrage
05-26-2008, 04:37 AM
lol edit to add the link, well not important thou

shackelberry
05-26-2008, 04:38 AM
atleast i think im rite cus ive seen lots of these 3 children 3 unknown ages riddles :rolleyes:

Gaaraxxx
05-26-2008, 11:47 AM
Shackel is right, well done :)!

Azn_InvaznXD
05-27-2008, 07:44 PM
Moar Riddalz Pl0xxxxxx

shackelberry
05-28-2008, 05:45 AM
dont call ppl nubs cos they didnt understand the riddle...
and if you knew the answear you shud have said rite away now no one believes you actually did know it...

horong
05-28-2008, 06:00 AM
more riddles instead of insults please

Cherushi
05-28-2008, 06:55 AM
i think flamsted was joking? O_o! coz if not... erm... no comment. lol D=

Gaaraxxx
05-28-2008, 10:35 AM
Lawlz.
Updating it now, give me a few ;)!

shackelberry
05-28-2008, 10:48 AM
Current Riddle:

A farmer offers his land to one of his two sons on this condition:
You shall race eachother on horse to the destination I specify, the loser shall be granted my land.
The two sons thought that this was an unfair gesture and couldn't find a just way to have the race.
They seek the words of a wise man.
Using his advice, the two sons race full-speed towards their destination.
What advice did the wise man give?

Worth: 4


Ahhh heard that one before just in my native language but the same riddle ahhhhh... think think think think............. got it!!!

The wise man said they shud switch horses so that the loosing horse wud get the fortune, so they both raced as fast as they cud to make there own horse loose...

Gaaraxxx
05-28-2008, 10:58 AM
Ya, they switched horses ;)!

Gaaraxxx
05-28-2008, 02:43 PM
New riddle updated :3

Elendira
05-28-2008, 03:26 PM
Current Riddle:

How would you divide up 1000$ in to ten piles such that no matter what amount you were asked for, you could choose any combination of the piles to satisfy.

Worth: 4


489
256
128
64
32
16
8
4
2
1

I think.

Gaaraxxx
05-28-2008, 04:56 PM
Yes, very nice :D!